An inverted tube barometer is kept on a lift | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The lift is moving downward with a deceleration $\alpha$. This means the net acceleration of the lift is directed upward.The effective acceleratio

Vedclass · Accepted Answer

Height of the mercury column in the lift will be $\frac{P_0}{\rho(g + \alpha)}$

Vedclass · Answer

(A) The lift is moving downward with a deceleration $\alpha$. This means the net acceleration of the lift is directed upward.The effective acceleration due to gravity $g_{eff}$ in the frame of the lift is given by $g_{eff} = g + a$,where $a$ is the magnitude of the deceleration.In a barometer,the atmospheric pressure $P_0$ is balanced by the pressure exerted by the mercury column of height $h$,which is given by $P = \rho g_{eff} h$.Equating the two,we get $P_0 = \rho (g + \alpha) h$.Solving for $h$,we get $h = \frac{P_0}{\rho (g + \alpha)}$.

An inverted tube barometer is kept on a lift moving downward with a deceleration $\alpha$. The density of mercury is $\rho$ and the acceleration due to gravity is $g$. If the atmospheric pressure is $P_0$,then:

Similar Questions

Variation of atmospheric pressure with height from the Earth is ................

The height of a mercury barometer is $75 \ cm$ at sea level and $50 \ cm$ at the top of a hill. The ratio of the density of mercury to that of air is $10^4$. The height of the hill is ....... $km$.

What would be the absolute pressure at a depth of $1 \,km$ below the ocean surface? [Given: density of water $\rho = 10^{3} \,kg/m^{3}$,$g = 10 \,m/s^{2}$,$1 \,atm = 1.01 \times 10^{5} \,N/m^{2}$]

On what factors does the pressure at any place depend? Explain.

Vedclass Test Series

Exam Paper Generator

Online Exam Module